Charles Law

The volume of a fixed mass of gas is directly proportional to its temperature at constant pressure.

Please move the slider and experiment with it.

VT

charleslaw

 

v ∝ t
v = k t
v = k t

As you can see, the line, when extended backwards crosses the x-axis at -273 C0. There is a special temperature when all gases have zero volume, called Absolute Temperature.
So, 0 T = -273 C
+ 273 => 273 T = 0C
+ t => (273 + t) T = t C
T = 273 + t, where t is the temperature in Celsius.

If the temperature and volume of a fixed mass of gas take the values of v1 T1and V2 T2 respectively, where T is absolute temperature,


V1 / T1 = V2 / T2


E.g.


The volume of a fixed mass of air is volume is 8 cm3 at 27 C0. Its temperature is raised to 127 C0, while keeping the pressure constant. Find the volume.


p1 = 20, v1 = 8, p2 = 40
According to Charles's law,
V1 / T1 = V2 / T2
8 / (273 + 27) = v2 / (273 + 127)
v2 = 10.6cm3



Please answer the following questions.


  1. The volume of a gas at 30C0 is 8 cm3. Find its volume when the temperature is 50C0 while pressure remains the same.
  2. The volume of a gas at constant temperature is plotted against temperature in Celsius. What do the gradient and intercept represent ?
  3. The volume of a gas at 30C0 is x cm3. Find x when the temperature is 50C0 while pressure remains the same.


 

 

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